Home
Class 12
CHEMISTRY
An aqueous solution is made by dissolvin...

An aqueous solution is made by dissolving 10g of glucose `(C_(6)H_(12)O_(6))` in 90g of water at 300K. If the vapour pressure of pure water at 300 K is 32.8 mm Hg, what would be the vapour pressure of the solution?

Text Solution

Verified by Experts

`(32.8-P_s)/32.8=(10/60)/(10/60+90/18)`
`(32.8-P_s)/32.8=0.16/(0.16+5)`
`(32.8-P_s)/32.8=0.03`
`32.8-P_s=1.017`
`P_s=31.7 mm of Hg`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGMENT (SECTION-A)|50 Videos

  • SOLUTIONS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGMENT (SECTION-B)|21 Videos

  • SOLUTIONS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGMENT (SECTION-J) AAKASH CHALLENGERS QUESTIONS|10 Videos

  • REDOX REACTIONS

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT SECTION - D|10 Videos

  • SOME BASIC CONCEPT OF CHEMISTRY

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT( SECTION - D) Assertion-Reason Type Questions|15 Videos

Similar Questions

Explore conceptually related problems

An aqueous solution of glucose is made by dissolving 10 g of glucose in 90 g water at 303 K. If the V.P. of pure water at 303 K be 32.8 mm Hg, what would be V.P. of the solution ?

An aqueous solution of glucose was prepared by dissolving 18g of glucose in 90g of water. The relative lowering in vapour pressure is

Vapour pressure of pure water at 23^@C is 19.8 torr . Calculate the vapour of 3m aqueous solution.

The vapour pressure of water is 12.3 kPa at 300 K . Calculate vapour pressure of 1 molal solution of a solute in it.

At room temperature, a dilute solution of urea is prepared by dissolving 0.60 g of urea in 360 g of water. If the vapour pressure of pure water at this temperature is 35 mm Hg, lowering of vapour pressure will be: (molar mass of urea =60 g "mol"^(-1) )

If common salt is dissolved in water, the vapour pressure of the solution will

18 g of glucose (C_(6)H_(12)O_(6)) is added to 178.2 g of water. The vapour pressure of water for this aqueous solution at 100^@C is :

A solution is made by dissolving 1.0 gurea and 2.0g sucrose in 100 g water at 298 K. predict the vapour pressure of solution if the vapour pressure of water at 298 Kis 23.756 torr.

6.0 g of urea (molecular mass = 60) was dissolved in 9.9 moles of water. If the vapour pressure of pure water is P^(@) , the vapour pressure of solution is :

A solution of a non-volatile solute in water freezes at -0.30^(@)C . The vapour pressure of pure water at 298 K is 23.51 mm Hg and K_(f) for water is 1.86 degree//molal . Calculate the vapour pressure of this solution at 298 K .