Calculate the `DeltaG^(@)` and equilibrium constant of the reaction at `27^(@)C`
`Mg+ Cu^(+2) hArr Mg^(+2) + Cu`
`E_(Mg^(2+)//Mg)^(@) = -2.37V, E_(Cu^(2+)//Cu)^(@) = +0.34V`

Explanation

To solve the problem, we need to calculate the standard Gibbs free energy change (ΔG°) and the equilibrium constant (Kc) for the reaction:

\[ \text{Mg} + \text{Cu}^{2+} \rightleftharpoons \text{Mg}^{2+} + \text{Cu} \]

Given:
- \( E^\circ_{\text{Mg}^{2+}/\text{Mg}} = -2.37 \, \text{V} \)
- \( E^\circ_{\text{Cu}^{2+}/\text{Cu}} = +0.34 \, \text{V} \)

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