`CH_(3)D+Cl_(2)underset( "(1 mole)")overset("hv")rarr` Product
The product is

Options

A. `CH_(2)DCl`
B. `CH_(3)Cl`
C. `CDCl_(3)`
D. `C Cl_(4)`

Answer

To solve the question regarding the reaction of CH₃D with Cl₂ in the presence of sunlight, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants and Reaction Type**:
- The reactants are CH₃D (methyl deuteride) and Cl₂ (chlorine gas).
- The reaction occurs in the presence of sunlight, indicating that it is a photochemical reaction.
- This reaction is classified as a free radical substitution reaction.

2. **Understand the Mechanism of Free Radical Substitution**:
- In a free radical substitution reaction, one atom in a molecule is replaced by another atom.
- In this case, one chlorine atom will replace either a hydrogen atom or a deuterium atom in CH₃D.

3. **Determine Possible Products**:
- The possible products from the substitution of chlorine for hydrogen or deuterium in CH₃D are:
- CH₂DCl (where one hydrogen is replaced by chlorine)
- CH₃Cl (where deuterium remains and one hydrogen is replaced by chlorine)

4. **Consider Bond Strengths**:
- The bond strength of the carbon-hydrogen (C-H) bond is weaker than that of the carbon-deuterium (C-D) bond.
- Since the C-D bond is stronger, it is less likely to break compared to the C-H bond.

5. **Predict the Major Product**:
- Given that the C-H bond is weaker, it is more likely to break during the reaction.
- Therefore, the chlorine will replace one of the hydrogen atoms, leading to the formation of CH₂DCl.

6. **Final Product**:
- The major product formed from the reaction of CH₃D with Cl₂ in sunlight is CH₂DCl.

### Conclusion:
The correct product of the reaction CH₃D + Cl₂ (in the presence of sunlight) is **CH₂DCl**.

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