Home
Class 12
CHEMISTRY
When 50% solution of H(2)SO(4) is electr...

When 50% solution of `H_(2)SO_(4)` is electrolysed by passing a current of high density at low temperature the main products of electrolysis are:

A

Oxygen & Hydrogen

B

`H_(2)` and peroxy disuphuric acid

C

`H_(2) and SO_(2)`

D

`O_(2)` and peroxy disulphuric acid

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of identifying the main products of electrolysis of a 50% solution of sulfuric acid (H₂SO₄), we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Electrolysis of H₂SO₄**: - When sulfuric acid is dissolved in water, it dissociates into hydrogen ions (H⁺) and bisulfate ions (HSO₄⁻). The electrolysis process involves the movement of these ions towards the electrodes. 2. **Identifying the Cathode Reaction**: - At the cathode, cations (H⁺ ions) migrate towards the negatively charged electrode. Each H⁺ ion gains an electron (reduction) to form hydrogen gas (H₂). - The reaction at the cathode can be represented as: \[ 2H^+ + 2e^- \rightarrow H_2(g) \] - Thus, hydrogen gas is produced at the cathode. 3. **Identifying the Anode Reaction**: - At the anode, anions (HSO₄⁻ ions) migrate towards the positively charged electrode. The oxidation of HSO₄⁻ ions occurs, leading to the formation of peroxodisulfuric acid (H₂S₂O₈). - The reaction at the anode can be represented as: \[ 2HSO_4^- \rightarrow H_2S_2O_8 + 2e^- \] - Therefore, peroxodisulfuric acid is produced at the anode. 4. **Summarizing the Overall Reaction**: - The overall reaction for the electrolysis of 50% H₂SO₄ can be summarized as: \[ 2H_2SO_4 \rightarrow H_2(g) + H_2S_2O_8 \] - This indicates that the main products of the electrolysis are hydrogen gas (H₂) and peroxodisulfuric acid (H₂S₂O₈). 5. **Choosing the Correct Option**: - From the options provided: 1. Oxygen and hydrogen 2. Hydrogen and peroxide disulfuric acid 3. Hydrogen and SO₂ gas 4. Oxygen and peroxide disulfuric acid - The correct answer is option 2: Hydrogen and peroxide disulfuric acid (H₂S₂O₈). ### Final Answer: The main products of electrolysis of a 50% solution of H₂SO₄ are hydrogen gas (H₂) and peroxodisulfuric acid (H₂S₂O₈). ---
Promotional Banner

Topper's Solved these Questions

  • HYDROGEN

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - C) (Previous type questions)|26 Videos
  • HYDROGEN

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - D) (Assertion-Reason Type question)|15 Videos
  • HYDROGEN

    AAKASH INSTITUTE ENGLISH|Exercise ASSIGNMENT (SECTION - A) (objective type question)|29 Videos
  • HYDROCARBONS

    AAKASH INSTITUTE ENGLISH|Exercise Assignment(Section - C) (Previous Years Questions)|60 Videos
  • M0ck test 26

    AAKASH INSTITUTE ENGLISH|Exercise EXAMPLE|43 Videos

Similar Questions

Explore conceptually related problems

when an aqueous solution of H_2SO_4 is electrolysed the product at anodes is :

Electrolysis of 50% H_(2)SO_(4) gives

A solution of CuSO_4 is electrolysed for 7 minutes with a current of 0.6A. The amount of electricity passed is equal to:

Volume of gases evolved when dill. H_(2)SO_(4) is electrolysed using 2F at STP

When a dilute aq. Solution of Li_(2)SO_(4) is electrolysed, the products formed at the anode and cathode are respectively ?

500 ml CuSO_(4) solution was electrolysed using a current of 2 amp (efficiency =75%) for 60 min calculate the pH of solution at the end of electrolysis (Assume initial pH=7)

If 9 gm H_(2)O is electrolysed completely with the current of 50 % efficiency then :

An aqueous solution of Na_2SO_4 is electrolysed using Pt electrodes. The products at the cathode and anode are respectively:

A: H_(2) and O_(2) are obtained if dil. Solution of Na_(2)SO_(4) is electrolysed using Pt electrodes. R: Platinum electrode is inert electrode.