Volume strength of `H_(2)O_(2)` labelled is `10 vol`. What is normality of `H_(2)O_(2)`?

Options

A. 2.1
B. 3.4
C. 1.7
D. 5.1

Answer

To find the normality of hydrogen peroxide (H₂O₂) given its volume strength, we can follow these steps:

### Step 1: Understand the relationship between volume strength and normality
The volume strength of a solution indicates how many volumes of gas are produced by one volume of the liquid when it decomposes. For hydrogen peroxide, the relationship between volume strength (VS) and normality (N) is given by the formula:
\[ \text{Volume Strength} = 5.6 \times \text{Normality} \]

### Step 2: Identify the given volume strength
From the question, we know that the volume strength of H₂O₂ is 10 volumes. This means:
\[ \text{Volume Strength} = 10 \, \text{vol} \]

### Step 3: Set up the equation using the relationship
Using the formula from Step 1, we can express normality in terms of volume strength:
\[ N = \frac{\text{Volume Strength}}{5.6} \]

### Step 4: Substitute the known value into the equation
Now, substituting the volume strength into the equation:
\[ N = \frac{10}{5.6} \]

### Step 5: Calculate the normality
Now, we perform the division:
\[ N = \frac{10}{5.6} \approx 1.7857 \]

### Step 6: Round to the appropriate significant figures
Normality is typically expressed to one decimal place, so we round 1.7857 to:
\[ N \approx 1.8 \]

However, the options provided in the question are:
1. 2.1
2. 3.4
3. 1.7
4. 5.1

The closest value to our calculated normality of 1.8 is 1.7.

### Final Answer
Thus, the normality of H₂O₂ is approximately **1.7 N**.

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