The volume of oxygen liberated from `15 ml` of 20 volume `H_(2)O_(2)` is

Options

A. 250 ml
B. 300 ml
C. 150 ml
D. 200 ml

Answer

To solve the question regarding the volume of oxygen liberated from 15 ml of 20 volume hydrogen peroxide (H₂O₂), we can follow these steps:

### Step-by-Step Solution:

1. **Understand Volume Strength**:
- The term "20 volume" means that 1 liter of hydrogen peroxide solution can liberate 20 liters of oxygen gas at normal temperature and pressure (NTP).

2. **Convert Volume Strength to Milliliters**:
- Since we are working with milliliters, we need to convert the volume strength into milliliters.
- 1 liter = 1000 milliliters, so:
\[ 20 \text{ liters of O}_2 = 20,000 \text{ milliliters of O}_2 \]
- This means that from 1000 ml of 20 volume H₂O₂, 20,000 ml of O₂ is liberated.

3. **Calculate Oxygen Liberated from 1 ml of H₂O₂**:
- To find out how much oxygen is liberated from 1 ml of H₂O₂, we divide the total volume of oxygen by the volume of the solution:
\[ \text{O}_2 \text{ from 1 ml H}_2\text{O}_2 = \frac{20,000 \text{ ml O}_2}{1000 \text{ ml H}_2\text{O}_2} = 20 \text{ ml O}_2 \]

4. **Calculate Oxygen Liberated from 15 ml of H₂O₂**:
- Now, we can find out how much oxygen is liberated from 15 ml of H₂O₂:
\[ \text{O}_2 \text{ from 15 ml H}_2\text{O}_2 = 15 \text{ ml H}_2\text{O}_2 \times 20 \text{ ml O}_2/\text{ml H}_2\text{O}_2 = 300 \text{ ml O}_2 \]

5. **Conclusion**:
- Therefore, the volume of oxygen liberated from 15 ml of 20 volume hydrogen peroxide is **300 ml**.

### Final Answer:
The volume of oxygen liberated from 15 ml of 20 volume H₂O₂ is **300 ml**.

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