The isomer of `C_(6)H_(14)` which will give maximum number of monochloroderivative is

Options

A. 2,3 -dimethylbutane
B. 2-methylpentane
C. 3-methylpentane
D. Hexane

Answer

To determine the isomer of \( C_6H_{14} \) that gives the maximum number of monochloroderivatives, we will analyze each of the given options step by step.

### Step 1: Identify the isomers of \( C_6H_{14} \)
The molecular formula \( C_6H_{14} \) corresponds to several structural isomers. The options provided are:
1. 2,3-Dimethylbutane
2. 2-Methylpentane
3. 3-Methylpentane
4. Hexane

### Step 2: Analyze each isomer for monochloroderivatives

#### Option A: 2,3-Dimethylbutane
- Structure:
\[ \text{CH}_3-\text{C}(\text{CH}_3)-\text{C}(\text{CH}_3)-\text{CH}_3 \]
- Identifying unique hydrogen atoms:
- There are 2 types of carbon atoms (2 CH groups and 4 CH3 groups).
- Possible monochloroderivatives:
- Substituting hydrogen from the two unique CH groups gives us 2 different products.

**Total Monochloroderivatives = 2**

#### Option B: 2-Methylpentane
- Structure:
\[ \text{CH}_3-\text{C}(\text{CH}_3)-\text{CH}_2-\text{CH}_2-\text{CH}_3 \]
- Identifying unique hydrogen atoms:
- The two CH3 groups are identical, but the other carbon atoms are unique.
- Possible monochloroderivatives:
- 1 from the first CH3, 1 from the second CH2, 1 from the third CH2, and 1 from the fourth carbon gives us 5 different products.

**Total Monochloroderivatives = 5**

#### Option C: 3-Methylpentane
- Structure:
\[ \text{CH}_3-\text{CH}_2-\text{C}(\text{CH}_3)-\text{CH}_2-\text{CH}_3 \]
- Identifying unique hydrogen atoms:
- The two CH2 groups are identical, and the other carbon atoms are unique.
- Possible monochloroderivatives:
- 1 from the first CH3, 1 from the second CH2, 1 from the third CH2, and 1 from the fourth carbon gives us 4 different products.

**Total Monochloroderivatives = 4**

#### Option D: Hexane
- Structure:
\[ \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_2-\text{CH}_3 \]
- Identifying unique hydrogen atoms:
- There are 3 pairs of identical CH2 groups.
- Possible monochloroderivatives:
- Substituting hydrogen from the terminal CH3 gives 1 product, and substituting from the 4 CH2 groups gives 3 more unique products.

**Total Monochloroderivatives = 3**

### Step 3: Compare the results
- 2,3-Dimethylbutane: 2 monochloroderivatives
- 2-Methylpentane: 5 monochloroderivatives
- 3-Methylpentane: 4 monochloroderivatives
- Hexane: 3 monochloroderivatives

### Conclusion
The isomer of \( C_6H_{14} \) that gives the maximum number of monochloroderivatives is **2-Methylpentane** with **5 monochloroderivatives**.

### Final Answer
**Option B: 2-Methylpentane**

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