Ethylidene chloride on treatement with aq. KOH gives

Options

A. Acetaldehyde
B. Ethylene glycol
C. Ethyl alcohol
D. Acetic acid

Answer

To solve the question regarding the reaction of ethylidene chloride with aqueous KOH, we can follow these steps:

### Step 1: Identify the Structure of Ethylidene Chloride
Ethylidene chloride, also known as 1,1-dichloroethane, has the chemical formula CH3CCl2H. It has two chlorine atoms attached to the same carbon atom.

### Step 2: Reaction with Aqueous KOH
When ethylidene chloride is treated with aqueous KOH, a nucleophilic substitution reaction occurs. The hydroxide ion (OH-) from KOH acts as a nucleophile and replaces one of the chlorine atoms.

### Step 3: Formation of the Intermediate
The reaction can be represented as follows:
\[ \text{CH}_3CCl_2H + \text{KOH} \rightarrow \text{CH}_3C(OH)Cl + \text{KCl} \]
Here, one chlorine atom is replaced by a hydroxyl group (OH), forming an intermediate compound.

### Step 4: Further Reaction
The intermediate can undergo further reaction, especially in the presence of heat or under certain conditions, leading to the elimination of HCl and the formation of acetyldehyde (CH3C(=O)H):
\[ \text{CH}_3C(OH)Cl \rightarrow \text{CH}_3C(=O)H + HCl \]

### Step 5: Conclusion
Thus, the final product of the reaction between ethylidene chloride and aqueous KOH is acetyldehyde.

### Final Answer
The correct answer is **acetyldehyde**.

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