`CH_2=CH2 + Br` = Product , what is product?

Answer

To determine the product of the reaction between ethylene (CH₂=CH₂) and bromine (Br₂), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are:
- Ethylene (CH₂=CH₂), which is an alkene with a double bond.
- Bromine (Br₂), which is a diatomic molecule.

### Step 2: Understand the Reaction Type
This reaction is an addition reaction. In this type of reaction, the double bond in the alkene will react with bromine, resulting in the addition of bromine atoms across the double bond.

### Step 3: Break the Double Bond
When bromine approaches the double bond in ethylene, the π bond (the double bond) will break. This allows for the formation of new bonds.

### Step 4: Formation of the Product
As the double bond breaks, each carbon atom that was part of the double bond will form a single bond with a bromine atom. Therefore, the product will have two bromine atoms added to the two carbon atoms.

### Step 5: Write the Product Structure
The resulting product can be represented as:
- CH₂Br-CH₂Br

This indicates that each carbon atom is now bonded to a bromine atom, resulting in 1,2-dibromoethane.

### Final Answer
The product of the reaction between CH₂=CH₂ and Br₂ is 1,2-dibromoethane (CH₂Br-CH₂Br).

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