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H(3)C-underset(CH(3))underset("| ")"CH"...

`H_(3)C-underset(CH_(3))underset("| ")"CH"-CH-=CH_(2)+HBrrarr(X)`
Here (X) (predominantly) is :

A

`CH_(3) - underset(CH_(3))underset(|)(CH)-underset(Br)underset(|)(CH)-CH_(3)`

B

`CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2)-CH_(2)Br`

C

`CH_(3) - underset(CH_(3))underset(|)(C )overset(Br)overset(|)(C ) - CH_(2) CH_(3)`

D

`CH_(3)-underset(Br)underset(|)(CH) - uderset(CH_(3))underset(|)(CH) - CH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
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The correct IUPAC name of the following compound is : CH_(3)CH_(2)-underset( CH_(3))underset(|)(C)H-CH=underset(C_(2)H_(5))underset(|)(C)-overset(C_(2)H_(5))overset(|)(C)H-CH_(2)-CH_(2)-CH_(2)-CH_(3)

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