Ethylene reacts with `S_(2)Cl_(2)` to give

Options

A. Mustard gas
B. Lewisite
C. Thiophene
D. Ethanethiol

Answer

To solve the question of what compound is formed when ethylene reacts with \( S_2Cl_2 \), we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are ethylene (C2H4) and sulfur dichloride (S2Cl2).

### Step 2: Write the Reaction
We can write the reaction between ethylene and sulfur dichloride:
\[ C_2H_4 + S_2Cl_2 \rightarrow ? \]

### Step 3: Determine the Product
When ethylene reacts with sulfur dichloride, it forms mustard gas, which is chemically known as bis(2-chloroethyl) sulfide. The reaction can be represented as:
\[ C_2H_4 + S_2Cl_2 \rightarrow (C_2H_4Cl_2S) \]
This compound is commonly referred to as mustard gas.

### Step 4: Balancing the Reaction
To balance the reaction, we can write:
\[ C_2H_4 + S_2Cl_2 \rightarrow C_2H_4Cl_2S \]
This shows that one molecule of ethylene reacts with one molecule of sulfur dichloride to produce mustard gas.

### Step 5: Conclusion
The product formed when ethylene reacts with \( S_2Cl_2 \) is mustard gas.

### Final Answer
The correct answer is mustard gas.

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