Actylene reacts with ammonical `Cu_(2)Cl_(2)` to give precipitate of

Options

A. Red colour
B. Yellow colour
C. White colour
D. Blue colour

Answer

To solve the question regarding the reaction of acetylene with ammonical `Cu2Cl2`, we can follow these steps:

### Step 1: Identify the Reactants
The reactants in this reaction are acetylene (C2H2) and ammonical `Cu2Cl2` (copper(I) chloride in the presence of ammonia).

### Step 2: Understand the Reaction
When acetylene reacts with ammonical `Cu2Cl2`, it forms a compound known as cuprous acetylide. This compound is formed due to the interaction between the acetylene and the cuprous ion (Cu^+) present in the ammonical solution.

### Step 3: Write the Reaction
The reaction can be represented as follows:
\[ 2 \text{Cu}_2\text{Cl}_2 + 2 \text{C}_2\text{H}_2 \rightarrow 2 \text{CuC}_2 + 4 \text{NH}_4\text{Cl} + 2 \text{H}_2\text{O} \]
Here, CuC2 is the cuprous acetylide which precipitates out of the solution.

### Step 4: Identify the Precipitate
The precipitate formed in this reaction is cuprous acetylide (CuC2), which is known to be red in color.

### Step 5: Conclusion
Based on the reaction and the precipitate formed, we conclude that the precipitate of the reaction between acetylene and ammonical `Cu2Cl2` is red in color.

### Final Answer
The precipitate formed is red in color.

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