Identify Z in the sequence of reaaction
`CH_(3)-CH_(2)-CH=CH_(2) overset(HBr)underset(H_(2)O_(2)//hv)to Z`

Options

A. `CH_(3)-CH_(2)-underset(Br)underset(|)CH-CH_(3)`
B. `CH_(3)-CH_(2)-CH_(2)-CH_(2)-Br`
C. `CH_(3)-underset(Br)underset(|)CH-CH=CH_(3)`
D. None of these

Answer

To identify the product Z in the given reaction sequence, we will analyze the reaction step by step.

### Step 1: Identify the Reactant
The starting material is 1-butene, represented as:
\[ \text{CH}_3-\text{CH}_2-\text{CH}=\text{CH}_2 \]

### Step 2: Understand the Reaction Conditions
The reaction involves the addition of HBr in the presence of hydrogen peroxide (H₂O₂) and light (hv). This indicates that the reaction will follow the anti-Markovnikov rule due to the presence of peroxide.

### Step 3: Apply the Anti-Markovnikov Rule
In anti-Markovnikov addition, the bromine (Br) will add to the less substituted carbon atom of the double bond, while the hydrogen (H) will add to the more substituted carbon atom.

### Step 4: Determine the Product
1. The double bond in 1-butene is between the second and third carbon atoms.
2. According to the anti-Markovnikov rule:
- The Br will attach to the terminal carbon (the one with more hydrogen atoms).
- The H will attach to the more substituted carbon.

Thus, the addition will proceed as follows:
- Br will add to the first carbon (C1).
- H will add to the second carbon (C2).

This results in the following structure:
\[ \text{CH}_3-\text{CH}_2-\text{CH}_2-\text{Br} \]

### Step 5: Name the Product
The resulting compound has four carbon atoms and a bromine substituent. Therefore, the product can be named as:
- 1-bromobutane or simply bromobutane.

### Conclusion
The product Z formed from the reaction is:
\[ \text{Z} = \text{1-bromobutane} \]

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