When silver chloride is treated with aqueous ammonia, the complex obtained is

Options

A. `[Ag(NH_3)_4]^oplus`
B. `[Ag(NH_3)_6]^oplus`
C. `[Ag(NH_3)_2]^oplus`
D. `[Ag(NH_3)(H_2O]^oplus`

Answer

To solve the question of what complex is formed when silver chloride (AgCl) is treated with aqueous ammonia (NH3), we can follow these steps:

### Step 1: Understand the Reactants
Silver chloride (AgCl) is a sparingly soluble salt. When it is treated with aqueous ammonia, we need to consider the interaction between AgCl and NH3.

**Hint:** Remember that ammonia can act as a ligand and can form complexes with metal ions.

### Step 2: Dissolution of Silver Chloride
When AgCl is added to aqueous ammonia, it begins to dissolve. This is because ammonia can coordinate with the silver ion (Ag⁺) and help to solubilize the compound.

**Hint:** Think about how ligands interact with metal ions to form soluble complexes.

### Step 3: Formation of the Complex
The silver ion (Ag⁺) can form a complex with ammonia. The reaction can be represented as:
\[ \text{AgCl} + 2 \text{NH}_3 \rightarrow [\text{Ag(NH}_3)_2]^+ + \text{Cl}^- \]

Here, the silver ion coordinates with two ammonia molecules to form the complex ion \([\text{Ag(NH}_3)_2]^+\).

**Hint:** Pay attention to the stoichiometry of the reaction; how many ammonia molecules are needed to form the complex?

### Step 4: Identify the Complex
The complex formed is specifically known as the silver diamine complex, which is \([\text{Ag(NH}_3)_2]^+\). This complex has a +1 charge.

**Hint:** Recall the naming conventions for coordination compounds; the number of ligands and the charge on the complex are important.

### Step 5: Conclusion
Thus, the complex obtained when silver chloride is treated with aqueous ammonia is \([\text{Ag(NH}_3)_2]^+\).

**Final Answer:** The complex obtained is \([\text{Ag(NH}_3)_2]^+\).

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