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In vapour state, sulphur (S2) shows para...

In vapour state, sulphur `(S_2)` shows paramagnetic behaviour due to

A

Presence of one unpaired electron in the antibonding `sigma^**` orbitals

B

Presence of two unpaired electrons in the bonding pi orbitals

C

Presence of one unpaired electrons in the bonding pi^** orbitals

D

Presence of two unpaired electrons in the antibonding pi^** orbitals

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The correct Answer is:
To understand why sulfur in its vapor state (S₂) exhibits paramagnetic behavior, we need to analyze the electronic configuration of the S₂ molecule and the presence of unpaired electrons. ### Step-by-Step Solution: 1. **Identify the Molecular Formula**: - The molecule in question is diatomic sulfur, represented as S₂. 2. **Determine the Electron Configuration**: - Each sulfur atom has an atomic number of 16, which means it has 16 electrons. - The electron configuration for a single sulfur atom is: \[ 1s^2 2s^2 2p^6 3s^2 3p^4 \] - For two sulfur atoms in S₂, the total number of electrons is \( 16 \times 2 = 32 \). 3. **Construct the Molecular Orbital Diagram**: - In the molecular orbital theory, the 32 electrons of S₂ will fill the molecular orbitals formed from the atomic orbitals of the two sulfur atoms. - The relevant molecular orbitals for S₂ are: - σ(1s), σ*(1s), σ(2s), σ*(2s), σ(2p_z), π(2p_x), π(2p_y), π*(2p_x), π*(2p_y). - The 3p orbitals will contribute to the formation of π and π* molecular orbitals. 4. **Filling the Molecular Orbitals**: - The filling of the molecular orbitals for S₂ will lead to the following configuration: \[ (σ(1s))^2 (σ*(1s))^2 (σ(2s))^2 (σ*(2s))^2 (σ(2p_z))^2 (π(2p_x))^2 (π(2p_y))^2 (π*(2p_x))^1 (π*(2p_y))^1 \] - This shows that there are two unpaired electrons in the π* orbitals. 5. **Conclusion on Paramagnetism**: - The presence of unpaired electrons in the π* orbitals leads to the paramagnetic behavior of the S₂ molecule. Paramagnetism occurs due to the presence of unpaired electrons that can align with an external magnetic field. ### Final Answer: Sulfur (S₂) in the vapor state shows paramagnetic behavior due to the presence of two unpaired electrons in the anti-bonding π* orbitals. ---
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