The sides of rectangular plate of mass 20 kg is 5 m x 4 m placed on a horizontal table. The pressure exerted by the block on the table is (Take `g = 10 m/s^2`)

Options

A. 10 Pa
B. 100 Pa
C. 20 Pa
D. 30 Pa

Answer

To find the pressure exerted by the rectangular plate on the table, we can follow these steps:

### Step-by-step Solution:

1. **Identify the given values:**
- Mass of the rectangular plate (m) = 20 kg
- Dimensions of the plate = 5 m (length) x 4 m (width)
- Acceleration due to gravity (g) = 10 m/s²

2. **Calculate the weight of the rectangular plate:**
The weight (W) of the plate can be calculated using the formula:
\[ W = m \cdot g \]
Substituting the values:
\[ W = 20 \, \text{kg} \cdot 10 \, \text{m/s}^2 = 200 \, \text{N} \]

3. **Calculate the area of the rectangular plate:**
The area (A) of the plate can be calculated using the formula:
\[ A = \text{length} \times \text{width} \]
Substituting the dimensions:
\[ A = 5 \, \text{m} \times 4 \, \text{m} = 20 \, \text{m}^2 \]

4. **Calculate the pressure exerted by the plate on the table:**
Pressure (P) is defined as the force (thrust) per unit area. Thus, we can use the formula:
\[ P = \frac{W}{A} \]
Substituting the values:
\[ P = \frac{200 \, \text{N}}{20 \, \text{m}^2} = 10 \, \text{N/m}^2 \]
Since \(1 \, \text{N/m}^2 = 1 \, \text{Pascal}\), we can say:
\[ P = 10 \, \text{Pa} \]

5. **Final Answer:**
The pressure exerted by the block on the table is **10 Pascal**.