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According to Archimedes's principle the ...

According to Archimedes's principle the loss in of weight is equal to (V is the volume displaced by the body, `rho` is the density of liquid in which body is immersed)

A

`Vrhog`

B

`2Vrhog`

C

`Vrhog/2`

D

`Vrhog/4`

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To solve the question regarding Archimedes's principle and the loss of weight when a body is immersed in a fluid, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding the Problem**: - We need to find the loss in weight of a body when it is immersed in a liquid. According to Archimedes's principle, this loss in weight is equal to the weight of the liquid displaced by the body. 2. **Identify the Variables**: - Let \( V \) be the volume of the liquid displaced by the body. - Let \( \rho \) be the density of the liquid in which the body is immersed. - The acceleration due to gravity is denoted as \( g \). 3. **Calculate the Weight of the Displaced Liquid**: - The weight of the liquid displaced can be calculated using the formula: \[ \text{Weight of displaced liquid} = \text{mass of displaced liquid} \times g \] - The mass of the displaced liquid can be expressed as: \[ \text{mass} = \text{density} \times \text{volume} = \rho \times V \] - Therefore, the weight of the displaced liquid becomes: \[ \text{Weight of displaced liquid} = \rho \times V \times g \] 4. **Relate True Weight and Apparent Weight**: - The true weight \( W \) of the body is given by: \[ W = m \times g \] - The apparent weight \( W' \) of the body when submerged in the liquid is given by: \[ W' = W - \text{Weight of displaced liquid} \] - Substituting the weight of the displaced liquid into the equation gives: \[ W' = W - \rho V g \] 5. **Determine the Loss in Weight**: - The loss in weight when the body is immersed in the liquid is the difference between the true weight and the apparent weight: \[ \text{Loss in weight} = W - W' = W - (W - \rho V g) = \rho V g \] 6. **Conclusion**: - According to Archimedes's principle, the loss in weight of the body when immersed in the liquid is equal to: \[ \text{Loss in weight} = \rho V g \] ### Final Answer: The loss in weight is equal to \( \rho V g \). ---
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