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If two liquids of same mass but densitie...

If two liquids of same mass but densities `rho_1` and `rho_2` respectively are mixed, then the density of the mixture is:

A

`p-1p_2(m_1 + m_2)/(m_1p_2 + m_2P1)`

B

`p-1p_2(m_1 + m_2)/(p_1 + p_2)`

C

`2p_1p_2/(p_1 + p_2)`

D

`(m_1p_1 + m_2p_2)/((m_1 + m_2)`

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The correct Answer is:
To find the density of a mixture of two liquids with the same mass but different densities, we can follow these steps: ### Step 1: Define the Variables Let: - Mass of each liquid = \( m \) - Density of the first liquid = \( \rho_1 \) - Density of the second liquid = \( \rho_2 \) ### Step 2: Calculate the Volumes of Each Liquid Using the formula for density, which is given by: \[ \text{Density} = \frac{\text{Mass}}{\text{Volume}} \] We can rearrange this to find the volume: \[ \text{Volume} = \frac{\text{Mass}}{\text{Density}} \] So, the volumes of the two liquids are: - Volume of the first liquid, \( V_1 = \frac{m}{\rho_1} \) - Volume of the second liquid, \( V_2 = \frac{m}{\rho_2} \) ### Step 3: Calculate the Total Volume of the Mixture The total volume of the mixture \( V \) is the sum of the volumes of the two liquids: \[ V = V_1 + V_2 = \frac{m}{\rho_1} + \frac{m}{\rho_2} \] ### Step 4: Simplify the Total Volume Factoring out \( m \) from the total volume: \[ V = m \left( \frac{1}{\rho_1} + \frac{1}{\rho_2} \right) \] ### Step 5: Calculate the Total Mass of the Mixture The total mass of the mixture \( M \) is: \[ M = m + m = 2m \] ### Step 6: Calculate the Density of the Mixture The density \( \rho \) of the mixture is given by: \[ \rho = \frac{\text{Total Mass}}{\text{Total Volume}} = \frac{M}{V} \] Substituting the values we found: \[ \rho = \frac{2m}{m \left( \frac{1}{\rho_1} + \frac{1}{\rho_2} \right)} \] ### Step 7: Simplify the Expression for Density Cancelling \( m \) from the numerator and denominator: \[ \rho = \frac{2}{\frac{1}{\rho_1} + \frac{1}{\rho_2}} \] This can be rewritten as: \[ \rho = \frac{2 \rho_1 \rho_2}{\rho_1 + \rho_2} \] ### Conclusion Thus, the density of the mixture of the two liquids is: \[ \rho = \frac{2 \rho_1 \rho_2}{\rho_1 + \rho_2} \]
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