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If M,mn and mp are masses (in kg) of nuc...

If M,`m_n` and `m_p` are masses (in kg) of nucleus `X_z^A`, neutron and proton respectively, then mass defect`(Deltam)` is equal to

A

`Deltam=[(A-Z)m_n+Am_p-M]`

B

`Deltam=[M-(A-Z)m_n+Am_p]`

C

`Deltam=[(A-Z)m_n+Zm_p+M]`

D

`Deltam=[(A-Z)m_n+Zm_p-M]`

Text Solution

AI Generated Solution

The correct Answer is:
To find the mass defect (Δm) of the nucleus \( X_Z^A \), we can follow these steps: ### Step 1: Identify the components of the nucleus The nucleus \( X_Z^A \) consists of: - \( Z \) protons - \( A - Z \) neutrons Where: - \( Z \) is the atomic number (number of protons) - \( A \) is the mass number (total number of nucleons, protons + neutrons) ### Step 2: Write the mass of the components The masses of the components are given as: - Mass of one proton = \( m_p \) - Mass of one neutron = \( m_n \) Thus, the total mass of the protons and neutrons can be calculated as: - Total mass of protons = \( Z \cdot m_p \) - Total mass of neutrons = \( (A - Z) \cdot m_n \) ### Step 3: Calculate the total mass of the nucleus The total mass of the nucleus \( M \) can be expressed as: \[ M = Z \cdot m_p + (A - Z) \cdot m_n \] ### Step 4: Define the mass defect The mass defect \( \Delta m \) is defined as the difference between the total mass of the individual nucleons (protons and neutrons) and the actual mass of the nucleus. Therefore, we can write: \[ \Delta m = \text{(mass of protons + mass of neutrons)} - \text{mass of nucleus} \] ### Step 5: Substitute the expressions Substituting the expressions from Step 2 and Step 3 into the equation for mass defect: \[ \Delta m = \left( Z \cdot m_p + (A - Z) \cdot m_n \right) - M \] ### Final Expression Thus, the mass defect can be expressed as: \[ \Delta m = (A - Z) \cdot m_n + Z \cdot m_p - M \] ### Conclusion The final expression for the mass defect \( \Delta m \) of the nucleus \( X_Z^A \) is: \[ \Delta m = (A - Z) m_n + Z m_p - M \]
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AAKASH INSTITUTE ENGLISH-Mock Test 39: PHYSICS-Example
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