The empirical formula of a compound is C...

The empirical formula of a compound is `CH_(2)O`. Its molecular weight is 90. Calculate the molecular formula of the compound.

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Formulae:
Molecular formula= n(Emperical formula)
`n=("Molecular Wt")/("Emperical Wt")=90/30=3`
:. Molecular formula =3 `(CH_(2)O)=C_(3)H_(6)O_(3)`
Given
Molecular Wt = 90
Emperical formula = `CH_(2)O`
:. Emperical wt =30

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The empirical formula of a compound is `CH_(2)O`. Its molecular weight is 90. Calculate the molecular formula of the compound.

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Topper's Solved these Questions

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