How much minimum volume of CO at STP is needed to react completely with 0.112 L of `O_(2)` at 1.5 atm. Pressure and `127^(@)C` to give `CO_(2)`.

Explanation

Formula `(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
`(1 xxV_(1))/(273)=(1.S xx 0.112)/(400)`
`V_(1)=(1.5x x 0.112 xx 273)/(400)`
=0.1147 lit
Chemical equation
2 CO + `O_(2)` `to 2CO_(2)`
2 moles of CO to 1 mole of `O_(2)` at STP
2 xx 22.4 lit to 1 xx 22.4 lit .
`larr` 0.1147 lit
`(0.1147 xx 2 xx 22.4)/(22.4)=0.2294` lit
The volume of CO required at STP= 0.2294 lit = 229.4 ml
At STP
`P_(1)=1" atm"`
`V_(1)=?`
`T_(1)=0^(@)C=273 K `
Given `P_(2)=1.5 ` at m
`V_(2)=0.112` " lit"
`T_(2)=127^(@)C=400 `K