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A carbon compound on analysis gave the f...

A carbon compound on analysis gave the following percentage composition, carbon 14.5%, hydrogen 1.8%, chlorine 64.46%, oxygen 19.24%. Calculate the empirical formula of the compound.

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:. The formula of the compound = `C_(1)H_(1.5)Cl_(1.5)O_(1)`
Emperical formula of the compound = `C_(2)H_(3)Cl_(3)O_(2)`.
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