A carbon compound contains 12.8% Carbon, 2.1% Hydrogen, 85.1% Bromine. The molecular weight of the compound is 187.9. Calculate the molecular formula.

Explanation

:. Emperical formula of the compound = `C_(1)H_(2)` Br
Molecular formula= n (Emperical formula)
n = `("Molecular Wt")/("Emperical Wt")=(187.9)/(94)=2`
:. Molecular formula = 2 `(CH_(2)Br)`
`C_(2)H_(4)Br_(2)`
Given molecular wt = 187.9
Emperical wt= 94 `(CH_(2)Br)`