Calculate the volume of oxygen gas required at STP conditions for the complete combustion of 10 cc of methane gas at `20^(@)C` and 770mm pressure.

Explanation

Given 10 cc of methane `(CH_(4))` undergoes combstion at `20^(@)C`and `770` mm pressure
STP Conditions
`P_(1)=760` mm
`V_(1)=?`
`T_(1)=273 k`
Formulae
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
`(760 x V_(1))/(273)=(770 xx10)/(293)`
`V_(1)=(770 xx 10x273)/(293 xx 760)=9.44 " CC" :. ` Volume of methane `(CH_(4))"at STP"=9.44 " CC".`
Given conditions
`P_(2)=770` mm
`V_(2)=10` cc
`T_(2)=20^(@)C=293" k"`
Chemical equation is
`CH_(4)+2O_(2)to CO_(2)+2H_(2)O`
1 mole `CH_(4)to` 2 moles of oxygen
22,400 cc of `CH_(4)to 2 xx 22400` cc of oxygen
9.44 cc of `CH_(4)to`?
`(9.44)/(22400)xx2xx22400=18.88` cc `:.` Volume of oxygen gas required STP = 18.88 cc.