Calculate the mass of sodium acetate `(CH_(3)COONa)` required to make 500 ml. of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245g `mol^(-1)`.

Explanation

Formula
Molarity = `("Wt")/("GM wt")xx(1000)/(V(m//))`
0.375 = `(Wt)/(82.0245)xx(1000)/(500)`
Wt = `(82.0245xx0.375)/(2)`
=15.3795.gms . `:."Mass of "CH_(3)COONa` required = 15.3795 gms
Molarity = 0.375 M
V=500 Ml
GMwt of `CH_(3)COONa=82.0245`