Chlorine is prepared in the laboratory by treating manganese dioxide `(MnO_(2))` with aqueous hydrochloric acid according to the reaction
`4HCl(aq)+MnO_(2)(s)to2H_(2)O(l)+MnCl_(2)(aq)+Cl_(2)(g)`
How many grams of HCl react with `5.0 g` of manganese dioxide ?

Explanation

Given chemical reaction is
`4HCl_((aq))+MnO_(2(s))to MnCl_(2(aq))+2H_(2)O_(l)+Cl_(2(g))`
4 " moles of HCl"to 1"mole of"` MnO_(2)`
4 xx 36.5 gms of HCl `to` 87 " gms of"`MnO_(2)`
? to 5" gms of"`MnO_(2)` `:.` Weight of HCl required = `(5x4xx36.5)/(87)=8.39` gms .