Assign oxidation number to the underlined elements in each of the following species.
a) `NaH_(2)underline(P)O_(4)" " b) NaHunderline(S)O_(4)" " c) H_(4)underline(P_(2))O_(7)`
d) `K_(2)underline(Mn)O_(4)" "e) Caunderline(O_(2))" " f) Naundeline(B)H_(4)`
g)`H_(2)underline(S_(2))O_(7)" " h) KAlunderline(SO_(4))_(2).12H_(2)O`

Explanation

`NaH_(2-)PO_(4)`
1(+1)+2(+1)+xx+4(-2)=0
1+2+xx-8=0
X-5=0
X=+5
Oxidation no. Of .P. in `NaH_(2)PO_(4)=+5`