Assign oxidation number to the underlined elements in each of the following species.
a) `NaH_(2)underline(P)O_(4)" " b) NaHunderline(S)O_(4)" " c) H_(4)underline(P_(2))O_(7)`
d) `K_(2)underline(Mn)O_(4)" "e) Caunderline(O_(2))" " f) Naundeline(B)H_(4)`
g)`H_(2)underline(S_(2))O_(7)" " h) KAlunderline(SO_(4))_(2).12H_(2)O`

Explanation

`H_(2)S_(2)O_(7)`
2(1)+2X + 7(-2)=0
2 + 2X -14 =0
2X-12 =0
X=+ 6
Oxidation state fo .S. in `H_(2)S_(2)O_(7)`=+6