Assign oxidation number to the underlined elements in each of the following species.
a) `NaH_(2)underline(P)O_(4)" " b) NaHunderline(S)O_(4)" " c) H_(4)underline(P_(2))O_(7)`
d) `K_(2)underline(Mn)O_(4)" "e) Caunderline(O_(2))" " f) Naundeline(B)H_(4)`
g)`H_(2)underline(S_(2))O_(7)" " h) KAlunderline(SO_(4))_(2).12H_(2)O`

Explanation

`KAl(SO_(4))_(2)12H_(2) :`
General formula of above compound is
`K_(2)SO_(4)`Al`(SO_(4))_(3)2+ H_(2)O` (Potash alum )
Consider `Al_(2)(SO_(4))_(3)` from the above double salt
2X+3(-2)=0
2X-6=0
X=+3