Balance the following redox reactions by ion-electron method :
`H_(2)O_(2)(aq)+Fe^(2+)(aq)to Fe^(3+)(aq)+H_(2)O(I)` (in acidic solution )

Explanation

`H_(2)O_(2)+Fe^(+2)to Fe^(+3)+H_(2)O` (Acidic medium)
Reduction half cell
`H_(2)O_(2)to H_(2)O`
`H_(2)O_(2)to H_(2)O+H_(2)O` (Oxygens balanced )
`H_(2)O_(2)+2H^(+)to 2H_(2)O` (Hydrogens balariced)
`overset(H_(2)O_(2)+2H^(+)+2e^(-)to 2H_(2)O("charge balanced"))overset(H_(2)O_(2)+2H^(+)+2e^(-)to 2H_(2)O)(2Fe^(+2)to2Fe^(+3)+2e^(-))/(2Fe^(+2)+H_(2)O_(2)+2H^(+)to 2Fe^(+3)+2H_(2)O)`