A carbon compound on analysis gave the following percentage composition, carbon 14.5%, hydrogen 1.8%, chlorine 64.46%, oxygen 19.24%. Calculate the empirical formula of the compound.

A compound on analysis gave the following percentage composition: C - 54.54%, H = 9.09%, 0 = 36.36%

Chemical analysis a carbon compound gave following percentage composition by weight of the element present, carbon = 10.06%, hydrogen = 0.84%, chlorine = 89.10%. Calculate the empirical formula of the compound.

Chemical analysis of a carbon compound gave the following percentage composition by weight of the elements present, carbon = 10.06% , hydrogen = 0.84% , chlorine = 89.10% . Calculate the empirical formula of the compound.

A compound on analysis gave the following percentage composition: Na=14.31% S = 9.97%, H = 6.22%, O = 69.5%, calcualte the molecular formula of the compound on the assumption that all the hydrogen in the compound is present in combination with oxygen as water of crystallisation. Molecular mass of the compound is 322 [Na = 23, S = 32, H = 1, 0 = 16].

A substance on analysis, gave the following percentage composition, Na = 43.4%, C = 11.3%, 0 = 43.3% calculate its empirical formula [Na = 23, C = 12, O = 16].

In which of the following percentage of carbon is maximum

What is the simplest formula of the compound which has the following percentage composition: Carbon 80%, hydrogen 20%.

An organic compound on analysis was found to contain 16.27% carbon. 0.67% Hydrogen, 72.2% chlorine. The V.D. of the compound is equal to 73.75. Calculate the empirical formula and molecular formula of the compound.

Analysis of a compound yields the following percentage composition. 65.03% of Ag, 15.68% Cr , 19.29% O. The simplest formula of the compound is [Cr At.wt=52]