Calculate the empirical formula of a compound having percentage composition:
Potassium (K) = 26.57, Chromium (Cr) = 35.36, Oxygen (O) = 38.07.
(Given the Atomic weights of K, Cr and O are 39, 52 and 16 respectively)

Analysis of a compound yields the following percentage composition. 65.03% of Ag, 15.68% Cr , 19.29% O. The simplest formula of the compound is [Cr At.wt=52]

Calculate the mass of oxygen obtained by complete decomposition of 10kg of pure potassium chlorate (Atomic mass K=39, O=16 and Cl = 35.5) 2KClO_3 to 2KCl + 3O_2

A substance on analysis, gave the following percentage composition, Na = 43.4%, C = 11.3%, 0 = 43.3% calculate its empirical formula [Na = 23, C = 12, O = 16].

A compound contains 26.57% potassium, 35.36% chromium and the remaining oxygen. What is its empirical formula? (At.wt. of K=39.1, Cr=52, 0=16)

A compound on analysis gave the following percentage composition: Na=14.31% S = 9.97%, H = 6.22%, O = 69.5%, calcualte the molecular formula of the compound on the assumption that all the hydrogen in the compound is present in combination with oxygen as water of crystallisation. Molecular mass of the compound is 322 [Na = 23, S = 32, H = 1, 0 = 16].

A compound has the following composition Mg = 9.76%,S = 13.01%, 0 = 26.01, H_2O = 51.22, what is its empirical formula? [Mg = 24, S = 32, O = 16, H = 1]

Calculate formula unit weight of ZnO,Na_2O,K_2CO_3 (given atomic weight of Zn=65u )

Write the net ionic equation for the reaction of potassium dichromate (VI), K_(2) Cr_(2) O_(7) with sodium sulphite, Na_(2)SO_(3) , in an acid solution to give chromium (III) ion and the sulphate ion.