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Solve tan^(2) theta = 1, theta in [-pi, ...

Solve `tan^(2) theta = 1, theta in [-pi, pi]`

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The correct Answer is:
`[-pi, pi]`
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If tan theta = 3/4 and theta is not in the first quadrant then (sin (pi//2 + theta)-cot(pi-theta))/(tan(3 pi//2 - theta)-cos (3pi//2+theta))=