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If sec x cos 5x + 1 =0, 0 lt x lt 2pi, t...

If `sec x cos 5x + 1 =0, 0 lt x lt 2pi`, then x =

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The correct Answer is:
`{(pi)/(6), (pi)/(4), (3pi)/(4), (5pi)/(6), (5pi)/(4), (7pi)/(6), (11pi)/(6), (7pi)/(4)}`
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