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If alpha, beta are solutions of a cos th...

If `alpha, beta` are solutions of `a cos theta + b sin theta = c` where a, b, `c in R` and `a^(2) + b^(2) gt 0, cos alpha ne cos beta, sin alpha ne sin beta` then prove that
`sin alpha sin beta = (c^(2)-a^(2))/(a^(2) + b^(2))`

Text Solution

Verified by Experts

The correct Answer is:
`sin alpha.sin beta = (c^(2) - a^(2))/(a^(2) + b^(2))`
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