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Solve sin 2x - cos 2x = sin x - cos x....

Solve sin 2x - cos 2x = sin x - cos x.

Text Solution

Verified by Experts

The correct Answer is:
`{2n pi//n in Z}uu{(2npi)/(3)-(pi)/(6)//n in Z}`
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Knowledge Check

  • If 3 cos x ne 2 sin x , then the general solution of sin^(2) x - cos 2x = 2 - sin 2x is x =

    A
    `n pi + (-1)^(n) (pi)/(2), n in Z`
    B
    `(n pi)/(2), n in Z`
    C
    `(4n pm 1)(pi)/(2), n in Z`
    D
    `(2n - 1) pi, n in Z`

  • If sin x - 3 sin 2x + sin 3x = cos x - 3 cos 2x + cos 3x then x =

    A
    `n pi + pi//8`
    B
    `n pi//2 + pi//8`
    C
    `(-1)^(2)n pi//2 + pi//8`
    D
    `2n pi + Cos^(-1)3//2`

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