If sinhx = 3/4 then find cosh 2x and sin...

If `sinhx = 3/4` then find `cosh 2x` and `sinh 2x`.

Text Solution

Verified by Experts

The correct Answer is:

`(15)/(8)`

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IF sinhx= 3//4 then find cosh2x and sinh2x.

sinhx=3//4 " then find" cosh2x and sinh2x.

Knowledge Check

If sinh x = 3/4 then sinh 3x =

A

`61//16`

B

`63//16`

C

`65//16`

D

`67//16`

cosh 2 x + sin h 2x =

A

`(1+ tan h(x))/(1-tan h(x))`

B

`(1-tan h x)/(1+tan h x)`

C

`(tan h x -1)/(tan h x + 1)`

D

`(1-tan h x)/(tan h x - 1)`

If cosh x = 3//4 , then cosh 2x =

A

`15//8`

B

`1//8`

C

`8//15`

D

`17//8`

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If cosh x = 5/4 then sinh 2x =

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If sinh(x)=(3)/(4) then sinh(3x) =

Cosh(2x) + sinh(2x) =

VIKRAM PUBLICATION ( ANDHRA PUBLICATION)-HYPERBOLIC FUNCTIONS -EXERCISE - 9(a)

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