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A metal piece of mass 50 g at 27^@C requ...

A metal piece of mass 50 g at `27^@`C requires 2400 J of heat energy in order to raise its temperature to `327^@`C. Calculate the specific heat capacity of the metal.

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Given : m = 50 g = 0.05 kg, heat energy required Q = 2400 J, rise in temperature `Delta`t = `(327 - 27)^@C` = `300^C` = 300 K
Specific heat capacity
c=`("heat energy Q")/("mass m"xx"rise in temperature"Deltat)`
`=("2400 J")/("0.05kg"xx"300 k")`=160 J `kg^(-1)K^(-1)`
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ICSE-CALORIMETRY-EXERCISE-11(B) (NUMERICALS)
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