Some heat energy is given to 120 g of water and its temperature rises by 10 K. When the same amount of heat energy is given to 60 g of oil, its temperature rises by 40 K. The specific heat capacity of water is 4200 J kg- `K^(-1)`. Calculate : (i) the amount of heat energy in joule given to water, and (ii) the specific heat capacity of oil.

Explanation

To solve the problem step by step, we will break it down into two parts as per the question.

### Part (i): Calculate the amount of heat energy given to water.

1. **Identify the given values**:
- Mass of water (m_water) = 120 g = 0.12 kg (since 1 g = 0.001 kg)
- Specific heat capacity of water (c_water) = 4200 J/(kg·K)
- Change in temperature (ΔT_water) = 10 K
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