40 g of water at `60^@`C is poured into a vessel containing 50 g of water at 20°C. The final temperature of mixture is 30°C. Taking the specific heat capacity of water as 4.2 J g-K-1, calculate the heat capacity of the vessel.

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the heat lost by the hot water
The heat lost by the hot water can be calculated using the formula:
\[ Q = m \cdot s \cdot \Delta T \]
Where:
- \( m \) = mass of the hot water = 40 g
- \( s \) = specific heat capacity of water = 4.2 J/g·K
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