What will be the result of mixing 400 g of copper chips at `500^@`C with 500 g of crushed ice at `0^@`C ?
Specific heat capacity of copper = 0.42 J `g^(-1) K^(-1)`, specific latent heat of fusion of ice = 340 J `g^(-1)`.

Explanation

Given, mass of copper chips = 400 g,
temperature of copper chips = `500^@`C,
mass of ice = 500 g
Heat energy imparted by copper chips in cooling from `500^@`C to `0^@`C
`Q_1 = 400 g xx 0.42 J g^(-1)K^(-1) xx (500 - 0)` K = 84000 J
Heat energy required to melt 500 g ice at `0^@`C
`Q_2 = 500 xx 340` = 170000 J
Since `Q_2 gt Q_1`, therefore all ice will not melt.
Let mg of ice melts, then
m `xx` 340 = 84000
`therefore` m=`(84000)/(340)` = 247 g
Thus only 247 g ice will melt and the temperature will remain `0^@`C.