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1300 J of heat energy is supplied to rai...

1300 J of heat energy is supplied to raise the temperature of 0.5 kg of lead from `20^@`C to `40^@`C. Calculate the specific heat capacity of lead.

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To calculate the specific heat capacity of lead, we can use the formula for heat energy: \[ Q = m \cdot S \cdot \Delta T \] Where: - \( Q \) = heat energy supplied (in joules) - \( m \) = mass of the substance (in kg) - \( S \) = specific heat capacity (in J/kg°C) ...
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