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An electric heater of power 600 W raises...

An electric heater of power 600 W raises the temperature of 4.0 kg of a liquid from `10.0^@`C to `15.0^@`C in 100 s. Calculate : (i) the heat capacity of 4.0 kg of liquid, and (ii) the specific heat capacity of liquid.

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To solve the problem, we will follow these steps: ### Given Data: - Power of the heater (P) = 600 W - Mass of the liquid (m) = 4.0 kg - Initial temperature (T1) = 10.0 °C - Final temperature (T2) = 15.0 °C - Time (t) = 100 s ...
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