Home
Class 10
PHYSICS
A mass of 50 g of a certain metal at 150...

A mass of 50 g of a certain metal at `150^@`C is immersed in 100 g of water at `11^@`C. The final temperature is `20^@`C. Calculate the specific heat capacity of the metal. Assume that the specific heat capacity of water is 4.2 `g^(-1)K^(-1)`

Text Solution

AI Generated Solution

To solve the problem, we will use the principle of calorimetry, which states that the heat lost by the metal will be equal to the heat gained by the water. ### Step-by-Step Solution: 1. **Identify the Given Data:** - Mass of the metal (m_m) = 50 g - Initial temperature of the metal (T_initial_m) = 150°C - Mass of water (m_w) = 100 g ...
Promotional Banner

Topper's Solved these Questions

  • CALORIMETRY

    ICSE|Exercise EXERCISE-11(B)|33 Videos

  • CALORIMETRY

    ICSE|Exercise EXERCISE-11(B) (MULTIPLE CHOICE TYPE)|2 Videos

  • CALORIMETRY

    ICSE|Exercise EXERCISE-11(A) (MULTIPLE CHOICE TYPE)|3 Videos

  • WORK ENERGY AND POWER

    ICSE|Exercise EXERCISE-2(C ) NUMERICALS|6 Videos

  • CURRENT ELECTRICITY

    ICSE|Exercise EXERCISE-8(C) NUMERICALS |35 Videos

Similar Questions

Explore conceptually related problems

A hot solid of mass 60 g at 100^(@)C is placed in 150 g of water at 20^(@)C . The final steady temperature recorded is 25^(@)C . Calculate the specific heat capacity of the solid. [Specific heat capacity of water = 4200 kg^(-1)""^(@)C^(-1) ]

A solid of mass 50 g at 150^(@) C is placed in 100 g of water at 11^(@)C , when the final temperature recorded is 20^(@)С . Find the specific heat capacity of the solid. (Specific heat capacity of water= 4.2 J//g^(@) C)

A metal piece of mass 20 g is heated to a constant temperature of 100^@ C. Then it is added in a calorimeter of mass 50 g and specific heat capacity 0.42 J g^(-1) K^(-1) , containing 50 g of water at 20^@ C. After stirring the water, the highest temperature recorded is 22^@ C. Calculate the specific heat capacity of metal. Specific heat capacity of water = 4.2 J g^(-1)K^(-1)

50 g of metal piece at 27^(@)C requires 2400 J of heat energy so as to attain a temperature of 327^(@)C . Calculate the specific heat capacity of the metal.

A metal piece of mass 50 g at 27^@ C requires 2400 J of heat energy in order to raise its temperature to 327^@ C. Calculate the specific heat capacity of the metal.

40 g of water at 60^@ C is poured into a vessel containing 50 g of water at 20°C. The final temperature of mixture is 30°C. Taking the specific heat capacity of water as 4.2 J g-K-1, calculate the heat capacity of the vessel.

A 50 g block of metal is heated to 200^(@)C and then dropped into a beaker containing 0.5 kg of water initially at 20^(@)C. if the final equilibrium temperature of the mixed system is 22.4^(@)C , find the specific heat capacity of the metal. Given, specific heat capacity of water is 4182 J kg^(-1).^(@)C^(-1) .

200 g of hot water at 80^@ C is added to 300 g of cold water at 10^@ C. Neglecting the heat taken by the container, calculate the final temperature of the mixture of water. Specific heat capacity of water = 4200 J kg^(-1)K^(-1)

Calculate the mass of ice needed to cool 150 g of water contained in a calorimeter of mass 50 g at 32^@ C such that the final temperature is 5^@ C. Specific heat capacity of calorimeter = 0.4 J g^(-1)^@C^(-1) , specific heat capacity of water = 4.2" J "g^(-1)""^@C^(-1) , latent heat capacity of ice = 330 J g^(-1) .

A piece of ice of mass 60 g is dropped into 140 g of water at 50^(@)C . Calculate the final temperature of water when all the ice has melted. (Assume no heat is lost to the surrounding) Specific heat capacity of water = 4.2Jg^(-1)k^(-1) Specific latent heat of fusion of ice = 336Jg^(-1)