Home
Class 10
PHYSICS
1.0 kg of water is contained in a 1.25 k...

1.0 kg of water is contained in a 1.25 kW kettle. Calculate the time taken for the temperature of water to rise from `25^@`C to its boiling point `100^@`C. Specific heat capacity of water = 4.2 J `g^(-1)K^(-1)`.

Text Solution

AI Generated Solution

To solve the problem of calculating the time taken for the temperature of 1.0 kg of water to rise from 25°C to 100°C using a 1.25 kW kettle, we can follow these steps: ### Step 1: Identify the given values - Mass of water (m) = 1.0 kg - Power of kettle (P) = 1.25 kW = 1250 W (since 1 kW = 1000 W) - Initial temperature (T_initial) = 25°C - Final temperature (T_final) = 100°C - Specific heat capacity of water (s) = 4.2 J/g·K = 4200 J/kg·K (after converting from grams to kilograms) ...
Promotional Banner

Topper's Solved these Questions

  • CALORIMETRY

    ICSE|Exercise EXERCISE-11(B)|33 Videos
  • CALORIMETRY

    ICSE|Exercise EXERCISE-11(B) (MULTIPLE CHOICE TYPE)|2 Videos
  • CALORIMETRY

    ICSE|Exercise EXERCISE-11(A) (MULTIPLE CHOICE TYPE)|3 Videos
  • WORK ENERGY AND POWER

    ICSE|Exercise EXERCISE-2(C ) NUMERICALS|6 Videos
  • CURRENT ELECTRICITY

    ICSE|Exercise EXERCISE-8(C) NUMERICALS |35 Videos

Similar Questions

Explore conceptually related problems

Calculate the heat energy required to raise the temperature of 2 kg of water from 10^@ C to 50^@ C. Specific heat capacity of water is 4200 J kg^(-1) K^(-1) .

Calculate the amount of heat energy required to raise the temperature of 100 g of copper from 20^@ C to 70^@ C. Specific heat capacity of copper = 390 J kg^(-1) K^(-1)

Calculate the difference in temperature between the water at the top and bottom of a water fall 200 m high. Specific heat capacity of water 42000 J kg ^(-1) K ^(-1).

A plate of area 10 cm^2 is to be electroplated with copper (density 9000 kg m^(-3) to a thickness of 10 micrometres on both sides, using a cell of 12 V . Calculate the energy spend by the cell in the process of deposition. If this energy is used to heat 100 g of water, calculate the rise in the temperature of the water. ECE of copper = 3 xx 10^(-7) kg C^(-1) and specific heat capacity of water = 4200 J kg^(-1) K^(-1) .

How much heat energy is gained when 5 kg of water at 20^(@)C is brought to its boiling point (Specific heat of water = 4.2 kj kg c)

Heat energy is supplied at a constant rate to 400 g of ice at 0^@ C. The ice is converted into water at 0^@ C in 5 minutes. How much time will be required to raise the temperature of water from 0^@ C to 100^@ C ? Specific latent heat of ice = 336 J g^(-1) , specific heat capacity of water = 4.2 J g^(-1)K^(-1)

200 g of hot water at 80^(@)C is added to 300 g of cold water at 10^(@)C . Calculate the final temperature of the mixture of water. Consider the heat taken by the container to be negligible. [specific heat capacity of water is 4200 Jkg^(-1)""^(@)C^(-1) ]

A calorimeter of negligible heat capacity contains 100cc of water at 40^(@)C . The water cools to 35^(@)C in 5minutes. The water is now replaced by k-oil of equal volume at 40^(@)C . Find the time taken for the temperature to become 35^(@)C under similar conditions. Specific heat cpacities of water and K-oil are 4200Jkg^(-1)K^(-1) and 2100Jkg^(-1)K^(-1) respectively. Density of K-oil =800kgm^(-3) .

A metal piece of mass 20 g is heated to a constant temperature of 100^@ C. Then it is added in a calorimeter of mass 50 g and specific heat capacity 0.42 J g^(-1) K^(-1) , containing 50 g of water at 20^@ C. After stirring the water, the highest temperature recorded is 22^@ C. Calculate the specific heat capacity of metal. Specific heat capacity of water = 4.2 J g^(-1)K^(-1)

200 g of hot water at 80^@ C is added to 300 g of cold water at 10^@ C. Neglecting the heat taken by the container, calculate the final temperature of the mixture of water. Specific heat capacity of water = 4200 J kg^(-1)K^(-1)