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How much heat energy is released when 5....

How much heat energy is released when 5.0 g of water at `20^@`C changes into ice at `0^@`C ? Take specific heat capacity of water = 4.2 J `g^(-1) K^(-1)`, specific latent heat of fusion of ice = 336 J `g^(-1)`.

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To find the total heat energy released when 5.0 g of water at 20°C changes into ice at 0°C, we need to consider two steps in the process: 1. Cooling the water from 20°C to 0°C. 2. Changing the water at 0°C to ice at 0°C. ### Step 1: Calculate the heat released while cooling the water from 20°C to 0°C The formula to calculate the heat released when cooling is given by: ...
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How much heat energy is released when 5 g of water at 20^(@)C changes to ice at 0^(@)C ? [Specific heat capacity of water = 4.2Jg^(-1)""^(@)C^(-1) Specific latent heat of fusion of ice = 336Jg^(-1) ]

A vessel of mass 100 g contains 150 g of water at 30^@ C. How much ice is needed to cool it to 5^@ C ? Take specific heat capacity of material of vessel = 0-4 J g^(-1) K^(-1) , specific latent heat of fusion of ice = 336 J g- and specific heat capacity of water = 4.2 J g^(-1) K^(-1) .

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How much boiling water at 100^@ C is needed to melt 2 kg of ice so that the mixture, which is all water, is at 0^@ C ? Given : specific heat capacity of water = 4.2 J g^(-1) K^(-1) , specific latent heat of ice = 336 J g^(-1) .

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