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The temperature of 170 g of water at 50^...

The temperature of 170 g of water at `50^@`C is lowered to `5^@`C by adding certain amount of ice to it. Find the mass of ice added. Given : Specific heat capacity of water = 4200 J `kg^(-1)^@C^(-1)` and specific latent heat of ice = 336000 J `kg^(-1)`.

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To solve the problem of finding the mass of ice added to the water, we will use the principle of calorimetry, which states that the heat lost by the water will be equal to the heat gained by the ice. ### Step-by-Step Solution: 1. **Identify the Given Data:** - Mass of water, \( m_w = 170 \, \text{g} = 0.17 \, \text{kg} \) - Initial temperature of water, \( T_{i,w} = 50^\circ C \) - Final temperature of water, \( T_f = 5^\circ C \) ...
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