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A piece of ice of mass 40 g is added to ...

A piece of ice of mass 40 g is added to 200 g of water at `50^@`C. Calculate the final temperature of water when all the ice has melted. Specific heat capacity of water = 4200 J `kg^(-1) K^(-1)` and specific latent heat of fusion of ice = 336 `xx 10^3" J "kg^(-1)`.

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To solve the problem of determining the final temperature of water when a piece of ice is added, we can follow these steps: ### Step 1: Identify the given data - Mass of ice (m_ice) = 40 g = 0.04 kg (since we need to convert grams to kilograms) - Mass of water (m_water) = 200 g = 0.2 kg - Initial temperature of water (T_water_initial) = 50 °C - Specific heat capacity of water (c_water) = 4200 J/(kg·K) - Specific latent heat of fusion of ice (L_f) = 336 × 10^3 J/kg ...
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