A ball is thrown vertically upwards with an initial velocity of 49 m `s^(-1)`. Calculate the time taken by it before it reaches the groung again (Take g= 9.8 m `s^(-2)`)

Explanation

To solve the problem of calculating the time taken by a ball thrown vertically upwards with an initial velocity of 49 m/s before it reaches the ground again, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the given values:**
- Initial velocity (u) = 49 m/s (upwards)
- Acceleration due to gravity (g) = 9.8 m/s² (downwards)
- Displacement (s) = 0 m (since the ball returns to the original position)
...