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Factorise : x^(2) + 5x + 6...

Factorise :
`x^(2) + 5x + 6`

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To factorise the expression \( x^2 + 5x + 6 \), we can follow these steps: ### Step 1: Identify the coefficients The expression is in the standard quadratic form \( ax^2 + bx + c \), where: - \( a = 1 \) (coefficient of \( x^2 \)) - \( b = 5 \) (coefficient of \( x \)) - \( c = 6 \) (constant term) ### Step 2: Find two numbers that multiply to \( ac \) and add to \( b \) We need to find two numbers that multiply to \( ac = 1 \times 6 = 6 \) and add up to \( b = 5 \). The pairs of factors of 6 are: - \( 1 \times 6 \) - \( 2 \times 3 \) Among these, the pair \( 2 \) and \( 3 \) adds up to \( 5 \): - \( 2 + 3 = 5 \) ### Step 3: Rewrite the middle term using the two numbers We can rewrite the expression by splitting the middle term \( 5x \) into \( 2x + 3x \): \[ x^2 + 2x + 3x + 6 \] ### Step 4: Group the terms Now, we can group the terms: \[ (x^2 + 2x) + (3x + 6) \] ### Step 5: Factor out the common factors from each group From the first group \( (x^2 + 2x) \), we can factor out \( x \): \[ x(x + 2) \] From the second group \( (3x + 6) \), we can factor out \( 3 \): \[ 3(x + 2) \] ### Step 6: Combine the factored groups Now we can combine the factored groups: \[ x(x + 2) + 3(x + 2) = (x + 2)(x + 3) \] ### Final Answer Thus, the factorised form of \( x^2 + 5x + 6 \) is: \[ (x + 2)(x + 3) \] ---
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